any and all in python3
# Here all the iterables are True so all
# will return True and the same will be printed
print (all([True, True, True, True]))
# Here the method will short-circuit at the
# first item (False) and will return False.
print (all([False, True, True, False]))
# This statement will return False, as no
# True is found in the iterables
print (all([False, False, False]))