Answers for "convert python code to c online"

convert python code to c online

# Raw Package
import numpy as np
import pandas as pd

#Data Source
import yfinance as yf

#Data viz
import plotly.graph_objs as go

#Interval required 1 minute
data = yf.download(tickers='UBER', period='1d', interval='1m')

#declare figure
fig = go.Figure()

#Candlestick
fig.add_trace(go.Candlestick(x=data.index,
                open=data['Open'],
                high=data['High'],
                low=data['Low'],
                close=data['Close'], name = 'market data'))

# Add titles
fig.update_layout(
    title='Uber live share price evolution',
    yaxis_title='Stock Price (USD per Shares)')

# X-Axes
fig.update_xaxes(
    rangeslider_visible=True,
    rangeselector=dict(
        buttons=list([
            dict(count=15, label="15m", step="minute", stepmode="backward"),
            dict(count=45, label="45m", step="minute", stepmode="backward"),
            dict(count=1, label="HTD", step="hour", stepmode="todate"),
            dict(count=3, label="3h", step="hour", stepmode="backward"),
            dict(step="all")
        ])
    )
)

#Show
fig.show()

convert python code to c online

option=int(input('Press 1 for generating hamming code  \nPress 2 for finding error in hamming code\n\t Enter your choice:--\n'))

if(option==1):  # GENERATE HAMMING CODE
    print('Enter the data bits')
    d=input()
    data=list(d)
    data.reverse()
    c,ch,j,r,h=0,0,0,0,[]

    while ((len(d)+r+1)>(pow(2,r))):
        r=r+1

    for i in range(0,(r+len(data))):
        p=(2**c)

        if(p==(i+1)):
            h.append(0)
            c=c+1

        else:
            h.append(int(data[j]))
            j=j+1

    for parity in range(0,(len(h))):
        ph=(2**ch)
        if(ph==(parity+1)):
            startIndex=ph-1
            i=startIndex
            toXor=[]

            while(i<len(h)):
                block=h[i:i+ph]
                toXor.extend(block)
                i+=2*ph

            for z in range(1,len(toXor)):
                h[startIndex]=h[startIndex]^toXor[z]
            ch+=1

    h.reverse()
    print('Hamming code generated would be:- ', end="")
    print(int(''.join(map(str, h))))


elif(option==2): # DETECT ERROR IN RECEIVED HAMMING CODE
    print('Enter the hamming code received')
    d=input()
    data=list(d)
    data.reverse()
    c,ch,j,r,error,h,parity_list,h_copy=0,0,0,0,0,[],[],[]

    for k in range(0,len(data)):
        p=(2**c)
        h.append(int(data[k]))
        h_copy.append(data[k])
        if(p==(k+1)):
            c=c+1
            
    for parity in range(0,(len(h))):
        ph=(2**ch)
        if(ph==(parity+1)):

            startIndex=ph-1
            i=startIndex
            toXor=[]

            while(i<len(h)):
                block=h[i:i+ph]
                toXor.extend(block)
                i+=2*ph

            for z in range(1,len(toXor)):
                h[startIndex]=h[startIndex]^toXor[z]
            parity_list.append(h[parity])
            ch+=1
    parity_list.reverse()
    error=sum(int(parity_list) * (2 ** i) for i, parity_list in enumerate(parity_list[::-1]))
    
    if((error)==0):
        print('There is no error in the hamming code received')

    elif((error)>=len(h_copy)):
        print('Error cannot be detected')

    else:
        print('Error is in',error,'bit')

        if(h_copy[error-1]=='0'):
            h_copy[error-1]='1'

        elif(h_copy[error-1]=='1'):
            h_copy[error-1]='0'
            print('After correction hamming code is:- ')
        h_copy.reverse()
        print(int(''.join(map(str, h_copy))))

else:
    print('Option entered does not exist')

convert python code to c online

x = 5
y = 10
print(x + y)

convert python code to c online

#Get the input via user interaction with the help of the variables w, v1, v1, v4
w=input('Enter the weight of the soil taken in grams:')
v1=input('Enter the volume of soil taken in ml:')
v2=input('Enter the volume of water added in ml:')
v4=input('Enter the volume of soil water at the end of the experiment in ml:')#calculation for soil+water, pore space volume
v3=float(v1)+float(v2)
v5=float(v3)-float(v4)#calculation for bulk density, particle density, pore space
bd=float(w)/float(v1)
pd=float(w)/(float(v1)-float(v5))
pps=(float(v5)/float(v1))*100  #print the soil+water, pore space volume, bulk density, particle density, pore space
print("volume of soil+water:",v3)
print(" pore space volume:",v5)
print("bulk density milligram per meter cube:",bd)
print("particle density:",pd)
print("percent pore space(in percentage):",pps)

convert python code to c online

def main(str1, str2):
    m = len(str1)
    n = len(str2)
    j = 0    
    i = 0
    while j < m and i < n:
        if str1[j] == str2[i]:
            j = j+1
        i = i + 1
    return j == m
str2 = str(input())
N = int(input())
for i in range(N):
    str1 = str(input())
    if main(str1, str2):
        print("POSITIVE") 
    else:
        print( "NEGATIVE")

convert python code to c online

ALGORITMO
DECLARE num[5,4] NUMÉRICO
 num_aux, i, j, k, l, m, n, lin, col NUMÉRICO
PARA i ← 1 ATÉ 5 FAÇA
INÍCIO
PARA j ← 1 ATÉ 4 FAÇA
INÍCIO
LEIA num_aux
IF i = 1 E j = 1
ENTÃO num[i, j] ← num_aux
SENÃO INICIO
 k ← 1
 l ← 1
 ENQUANTO num[k, l] < num_aux E (k  i OU l  j) FAÇA
 INÍCIO
 l ← l + 1
 SE l > 4
 ENTÃO INÍCIO
 k ← k + 1
 l ← 1
 FIM
 FIM
 m ← i;
 n ← j;
 ENQUANTO m  k OU n  l FAÇA
 INÍCIO
 SE n-1 < 1 ENTÃO
 INÍCIO
 lin ← m-1
 col ← 4
 FIM
 SENÃO INÍCIO
 lin ← m
 col ← n-1
 FIM
 num[m][n] ← num[lin][col]
 n ← n-1
 SE n < 1
 ENTÃO INÍCIO
 n ← 4
 m ← m-1
 FIM
 FIM
 num[k][l] ← num_aux
 FIM
FIM
FIM
PARA i ← 1 ATÉ 5 FAÇA
INÍCIO
PARA j ← 1 ATÉ 4 FAÇA
INÍCIO
ESCREVA “Elemento da posição “, i, “-”, j, “ = “, num[i][j]
FIM
FIM
FIM_ALGORITMO.

convert python code to c online

# cook your dish here
tc = int(input())
for _ in range(tc):
    c = 0
    n = int(input())
    n = pow(2,n)
    for x in range(0,n):
        a = x ^ (x+1)
        b = (x+2) ^ (x+3)
        if(a==b):
            c+=1
    print(c)

convert python code to c online

importmath #Get the inputs via user interaction with help of variables Na ,Ca ,Mg
Na=input ('Enter the value of Na+:')
Ca=input ('Enter the value of Ca2:')
Mg=input ('Enter the value of Mg2+:')#Calculation based on the formula
sar=float(Na)/(math.sqrt((float(Ca)+float(Mg))/2))
#Print the SAR
print("SAR:",sar)#Control flow statement for remarks
if sar>=0and sar<=10:
print("water class=s1 Low sodium hazard Remarks: Little or no hazard")
elif sar>=10and sar<=18:
print("water class=s2 Medium sodium hazard  Remarks: Appreciable hazard but can be used with appropriate management techniques")
elif sar>=18and sar<=26:
print("water class=s3 high sodium hazard  Remarks: Unsatisfactory for most of the crops")
elif sar>=26:
print("water class=s4 very high sodium hazard  Remarks: Not suitable")

convert python code to c online

''' Program for identify the Bulk density, Particle density, Percent pore space in python (pore space cylinder method)'''
#Get the input via user interaction with the help of the variables w, v1, v1, v4
w=input('Enter the weight of the soil taken in grams:')
v1=input('Enter the volume of soil taken in ml:')
v2=input('Enter the volume of water added in ml:')
v4=input('Enter the volume of soil water at the end of the experiment in ml:')#calculation for soil+water, pore space volume
v3=float(v1)+float(v2)
v5=float(v3)-float(v4)#calculation for bulk density, particle density, pore space
bd=float(w)/float(v1)
pd=float(w)/(float(v1)-float(v5))
pps=(float(v5)/float(v1))*100  #print the soil+water, pore space volume, bulk density, particle density, pore space
print("volume of soil+water:",v3)
print(" pore space volume:",v5)
print("bulk density milligram per meter cube:",bd)
print("particle density:",pd)
print("percent pore space(in percentage):",pps)

convert python code to c online

ALGORITMO
DECLARE num[5,4] NUMÉRICO
 num_aux, i, j, k, l, m, n, lin, col NUMÉRICO
PARA i ← 1 ATÉ 5 FAÇA
INÍCIO
PARA j ← 1 ATÉ 4 FAÇA
INÍCIO
LEIA num_aux
IF i = 1 E j = 1
ENTÃO num[i, j] ← num_aux
SENÃO INICIO
 k ← 1
 l ← 1
 ENQUANTO num[k, l] < num_aux E (k  i OU l  j) FAÇA
 INÍCIO
 l ← l + 1
 SE l > 4
 ENTÃO INÍCIO
 k ← k + 1
 l ← 1
 FIM
 FIM
 m ← i;
 n ← j;
 ENQUANTO m  k OU n  l FAÇA
 INÍCIO
 SE n-1 < 1 ENTÃO
 INÍCIO
 lin ← m-1
 col ← 4
 FIM
 SENÃO INÍCIO
 lin ← m
 col ← n-1
 FIM
 num[m][n] ← num[lin][col]
 n ← n-1
 SE n < 1
 ENTÃO INÍCIO
 n ← 4
 m ← m-1
 FIM
 FIM
 num[k][l] ← num_aux
 FIM
FIM
FIM
PARA i ← 1 ATÉ 5 FAÇA
INÍCIO
PARA j ← 1 ATÉ 4 FAÇA
INÍCIO
ESCREVA “Elemento da posição “, i, “-”, j, “ = “, num[i][j]
FIM
FIM
FIM_ALGORITMO.