iterator in python
# define a list
my_list = [4, 7, 0, 3]
# get an iterator using iter()
my_iter = iter(my_list)
# iterate through it using next()
# Output: 4
print(next(my_iter))
# Output: 7
print(next(my_iter))
# next(obj) is same as obj.__next__()
# Output: 0
print(my_iter.__next__())
# Output: 3
print(my_iter.__next__())
# This will raise error, no items left
next(my_iter)how to create a break in iterating a sequence with a specific set of values in python
>>> d = {'foo': 1, 'bar': 2, 'baz': 3}
>>> for k, v in d.items():
... print('k =', k, ', v =', v)
...
k = foo , v = 1
k = bar , v = 2
k = baz , v = 3python iterator
pies = ["cherry", "apple", "pumpkin", "pecan"]
iterator = iter(pies)
print(next(iterator))
#prints "cherry" because it's the current one being iterated overhow to use iteration in python
n = 5
while n > 0:
print n
n = n-1
print 'Blastoff!'python for loop iterator
import numpy as np
# With array cycling
arr = np.array([1,2,3,4,5,6,7,8,9])
for i in range(len(arr)):
# logic with iterator use (current logic replaces even numbers with zero)
if arr[i] % 2 == 0: arr[i] = 0
print(arr)
# Output: [1, 0, 3, 0, 5, 0, 7, 0 , 9]Copyright © 2021 Codeinu
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