Answers for "TypeError: __call__() missing 1 required positional argument: 'send'"

5

python missing 1 required positional argument:

def your_method(self, arg1, arg2): # you must add the "self" argument in 1st position
'''
This kind of error happens when working with classes
When you create methods for a class, you must always pass self as the first argument
self designates the object in which it is called
'''
# for instance : 
class Dog: # let create a class Dog
  def __init__(self, color, age): # when you create a new Dog object, two parameters are required
    self.color = color # here, whe use self to attach the attribute to this Dog object
    self.age = age
    self.bark("Woof")
    
  def bark(self, message): # your error might come from the fact you forgot to add the self element as the first argument in, at least, one method
    print(message)
    
'''
This is a very simple example but it stays true for every class
You have to pass self as the first argument for each method
'''
Posted by: Guest on May-12-2021
0

TypeError: load() missing 1 required positional argument: 'action_id'

<button type="action"    name="%(mrp.action_change_production_qty)d"    string="Update" states="confirmed,planned,progress" class="oe_link"/>
Posted by: Guest on August-19-2021

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