fibonacci
# WARNING: this program assumes the
# fibonacci sequence starts at 1
def fib(num):
"""return the number at index `num` in the fibonacci sequence"""
if num <= 2:
return 1
return fib(num - 1) + fib(num - 2)
# method 2: use `for` loop
def fib2(num):
a, b = 1, 1
for _ in range(num - 1):
a, b = b, a + b
return a
print(fib(6)) # 8
print(fib2(6)) # same result, but much fasterfibonacci
# Easy fibonacci exercise
# Method #1
def fibonacci(n):
# 1th: 0
# 2th: 1
# 3th: 1 ...
if n == 1:
return 0
elif n == 2:
return 1
else:
return fibonacci(n - 1) + fibonacci(n - 2)
# Method #2
def fibonacci2(n):
if n == 0: return 0
n1 = 1
n2 = 1
# (1, n - 2) because start by 1, 2, 3... not 0, 1, 1, 2, 3....
for i in range(1, n - 2):
n1 += n2
n2 = n1 - n2
return n1
print(fibonacci(13))
# return the nth element in the fibonacci sequencefibinachi
def fib(n):
lisp = []
for i in range(n):
if len(lisp) < 3:
if len(lisp) == 0:
lisp.append(0)
else:
lisp.append(1)
else:
lisp.append(lisp[len(lisp)-1]+lisp[len(lisp)-2])
return lispfibonacci
f(n) = f(n-1) + f(n-2)
f(6)
^
/\
f(5) + f(4)
^
/\ + /\
f(4) + f(3) f(3) + f(2)
^ ^ ^ ^
/\ /\ /\ /\
f(3) + f(2) f(2) +f(1) f(2) + f(1) f(1) + f(0)
^ ^ ^ ^
/\ /\ /\ /\
f(2) + f(1) f(1) + f(0) f(1)+ f(0) f(1) + f(0)
^
/\
f(1) + f(0)
//f(6) = 8 ==> f(1)*8 f(1) appears 8 times
double feb = (1/Math.pow(5,0.5)) * (Math.pow((1+Math.pow(5,0.5))/2,n)) - (1/Math.pow(5,0.5))* (Math.pow((1-Math.pow(5,0.5))/2,n));
f(1) == 1;Fibonacci
import java.util.Scanner;
public class Fibonacci
{
public static void main(String[] args)
{
int n, a = 0, b = 0, c = 1;
Scanner s = new Scanner(System.in);
System.out.print("Enter value of n:");
n = s.nextInt();
System.out.print("Fibonacci Series:");
for(int i = 1; i <= n; i++)
{
a = b;
b = c;
c = a + b;
System.out.print(a+" ");
}
}
}fibanachi
function fib(n){
var fib = [0, 1];
var i = 0;
for (let i = 0; i != n-2; i++){
fib.push(fib[i]+fib[i+1]);
}
return fib;
}Copyright © 2021 Codeinu
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