fibonacci
# WARNING: this program assumes the
# fibonacci sequence starts at 1
def fib(num):
"""return the number at index `num` in the fibonacci sequence"""
if num <= 2:
return 1
return fib(num - 1) + fib(num - 2)
# method 2: use `for` loop
def fib2(num):
a, b = 1, 1
for _ in range(num - 1):
a, b = b, a + b
return a
print(fib(6)) # 8
print(fib2(6)) # same result, but much fasterfibonacci
# Easy fibonacci exercise
# Method #1
def fibonacci(n):
# 1th: 0
# 2th: 1
# 3th: 1 ...
if n == 1:
return 0
elif n == 2:
return 1
else:
return fibonacci(n - 1) + fibonacci(n - 2)
# Method #2
def fibonacci2(n):
if n == 0: return 0
n1 = 1
n2 = 1
# (1, n - 2) because start by 1, 2, 3... not 0, 1, 1, 2, 3....
for i in range(1, n - 2):
n1 += n2
n2 = n1 - n2
return n1
print(fibonacci(13))
# return the nth element in the fibonacci sequencefibonacii sequence code
# Program to display the Fibonacci sequence up to n-th term
nterms = int(input("How many terms? "))
# first two terms
n1, n2 = 0, 1
count = 0
# check if the number of terms is valid
if nterms <= 0:
print("Please enter a positive integer")
elif nterms == 1:
print("Fibonacci sequence upto",nterms,":")
print(n1)
else:
print("Fibonacci sequence:")
while count < nterms:
print(n1)
nth = n1 + n2
# update values
n1 = n2
n2 = nth
count += 1fibinachi
def fib(n):
lisp = []
for i in range(n):
if len(lisp) < 3:
if len(lisp) == 0:
lisp.append(0)
else:
lisp.append(1)
else:
lisp.append(lisp[len(lisp)-1]+lisp[len(lisp)-2])
return lispFibonacci
import java.util.Scanner;
public class Fibonacci
{
public static void main(String[] args)
{
int n, a = 0, b = 0, c = 1;
Scanner s = new Scanner(System.in);
System.out.print("Enter value of n:");
n = s.nextInt();
System.out.print("Fibonacci Series:");
for(int i = 1; i <= n; i++)
{
a = b;
b = c;
c = a + b;
System.out.print(a+" ");
}
}
}fibonacci
fib(5)
/
fib(4) fib(3)
/ /
fib(3) fib(2) fib(2) fib(1)
/ / /
fib(2) fib(1) fib(1) fib(0) fib(1) fib(0)
/
fib(1) fib(0)Copyright © 2021 Codeinu
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