Answers for "fibonacci sequence of numbers"

1

fibonacci sequence

public class Numbers {
	public static void FibannaciNumbers(int n) {
        int x = 0;
        int y = 1;
        if(n >= 1) {
            System.out.print(x + " ");
        }
        if(n >= 2) {
            System.out.print(y);
        }
        if (n > 2) {
            for(int a = n - 2; a > 0; a--) {
                int z = y + x;
                System.out.print(" " + z);
                x = y;
                y = z;
            }
        }
    }
}
Posted by: Guest on August-23-2021
1

fibonacci sequence

public class Numbers {
	public static void FibannaciNumbers(int n) {
        int x = 0;
        int y = 1;
        if(n >= 1) {
            System.out.print(x + " ");
        }
        if(n >= 2) {
            System.out.print(y);
        }
        if (n > 2) {
            for(int a = n - 2; a > 0; a--) {
                int z = y + x;
                System.out.print(" " + z);
                x = y;
                y = z;
            }
        }
    }
}
Posted by: Guest on August-23-2021
-1

fibonacci numbers

f(n) = f(n-1) + f(n-2) 
                                  f(6)
                                   ^
  			                       /\
                f(5)               +                       f(4)
                ^
               /\                                           /\
                
        f(4)    +           f(3)                     f(3)    +    f(2)
       ^                       ^                     ^              ^
      /\                       /\                    /\            /\
   
 f(3)   +       f(2)            f(2) +f(1)       f(2) + f(1)   f(1) +  f(0)             
   ^              ^                ^                ^
   /\             /\                /\              /\
    
f(2) + f(1)      f(1) +  f(0)     f(1)+ f(0)       f(1) + f(0)         
  ^
  /\
f(1) +  f(0) 
  
//f(6) = 8   ==>  f(1)*8    f(1) appears 8 times 
 double feb  = (1/Math.pow(5,0.5)) * (Math.pow((1+Math.pow(5,0.5))/2,n)) - (1/Math.pow(5,0.5))* (Math.pow((1-Math.pow(5,0.5))/2,n));  
  
f(1) == 1;
Posted by: Guest on August-01-2021
-1

fibonacci numbers

f(n) = f(n-1) + f(n-2) 
                                  f(6)
                                   ^
  			                       /\
                f(5)               +                       f(4)
                ^
               /\                                           /\
                
        f(4)    +           f(3)                     f(3)    +    f(2)
       ^                       ^                     ^              ^
      /\                       /\                    /\            /\
   
 f(3)   +       f(2)            f(2) +f(1)       f(2) + f(1)   f(1) +  f(0)             
   ^              ^                ^                ^
   /\             /\                /\              /\
    
f(2) + f(1)      f(1) +  f(0)     f(1)+ f(0)       f(1) + f(0)         
  ^
  /\
f(1) +  f(0) 
  
//f(6) = 8   ==>  f(1)*8    f(1) appears 8 times 
 double feb  = (1/Math.pow(5,0.5)) * (Math.pow((1+Math.pow(5,0.5))/2,n)) - (1/Math.pow(5,0.5))* (Math.pow((1-Math.pow(5,0.5))/2,n));  
  
f(1) == 1;
Posted by: Guest on August-01-2021

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