Answers for "fibonachi sequence"

10

fibbonacci

0, 1, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89, 144, 233, 377, 610, 987, 1597, 2584, 4181, 6765, 10946, 17711, 28657, 46368, 75025, 121393, 196418, 317811,
Posted by: Guest on February-01-2021
10

fibbonacci

0, 1, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89, 144, 233, 377, 610, 987, 1597, 2584, 4181, 6765, 10946, 17711, 28657, 46368, 75025, 121393, 196418, 317811,
Posted by: Guest on February-01-2021
1

fibonacci sequence

public class Numbers {
	public static void FibannaciNumbers(int n) {
        int x = 0;
        int y = 1;
        if(n >= 1) {
            System.out.print(x + " ");
        }
        if(n >= 2) {
            System.out.print(y);
        }
        if (n > 2) {
            for(int a = n - 2; a > 0; a--) {
                int z = y + x;
                System.out.print(" " + z);
                x = y;
                y = z;
            }
        }
    }
}
Posted by: Guest on August-23-2021
1

fibonacci sequence

public class Numbers {
	public static void FibannaciNumbers(int n) {
        int x = 0;
        int y = 1;
        if(n >= 1) {
            System.out.print(x + " ");
        }
        if(n >= 2) {
            System.out.print(y);
        }
        if (n > 2) {
            for(int a = n - 2; a > 0; a--) {
                int z = y + x;
                System.out.print(" " + z);
                x = y;
                y = z;
            }
        }
    }
}
Posted by: Guest on August-23-2021
1

Fibonacci sequence

function myFib(n) {
    if (isNaN(n) || Math.floor(n) !== n)
        return "Not an integer value!";
    if (n === 0 || n === 1)
        return 3;
    else
        return myFib(n - 1) + myFib(n - 2);
}

console.log(myFib(5));
Posted by: Guest on August-17-2021
1

Fibonacci sequence

function myFib(n) {
    if (isNaN(n) || Math.floor(n) !== n)
        return "Not an integer value!";
    if (n === 0 || n === 1)
        return 3;
    else
        return myFib(n - 1) + myFib(n - 2);
}

console.log(myFib(5));
Posted by: Guest on August-17-2021
1

fibinachi

def fib(n):
  lisp = []
  
  for i in range(n):
    if len(lisp) < 3:
      if len(lisp) == 0:
        lisp.append(0)
      else:
        lisp.append(1)
    
    else:
      lisp.append(lisp[len(lisp)-1]+lisp[len(lisp)-2])
  
  return lisp
Posted by: Guest on October-13-2020
1

fibinachi

def fib(n):
  lisp = []
  
  for i in range(n):
    if len(lisp) < 3:
      if len(lisp) == 0:
        lisp.append(0)
      else:
        lisp.append(1)
    
    else:
      lisp.append(lisp[len(lisp)-1]+lisp[len(lisp)-2])
  
  return lisp
Posted by: Guest on October-13-2020
1

fibonacci sequence

int n ; 
double feb  = (1/Math.pow(5,0.5)) * (Math.pow((1+Math.pow(5,0.5))/2,n)) - (1/Math.pow(5,0.5))* (Math.pow((1-Math.pow(5,0.5))/2,n));
Posted by: Guest on August-01-2021
1

fibonacci sequence

int n ; 
double feb  = (1/Math.pow(5,0.5)) * (Math.pow((1+Math.pow(5,0.5))/2,n)) - (1/Math.pow(5,0.5))* (Math.pow((1-Math.pow(5,0.5))/2,n));
Posted by: Guest on August-01-2021

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