Answers for "datetime.timedelta to string"

11

python datetime string

import datetime

today = datetime.datetime.now()
date_time = today.strftime("%m/%d/%Y, %H:%M:%S")
print("date and time:",date_time)
Posted by: Guest on May-21-2020
0

phyton 2.7 convert timedelta to string

import datetime
start = datetime.datetime(2009,2,10,14,00)
end   = datetime.datetime(2009,2,10,16,00)
delta = end-start
print(str(delta))
# prints 2:00:00
Posted by: Guest on September-03-2020
0

datetime.timedelta format to string python

s = 13420
hours, remainder = divmod(s, 3600)
minutes, seconds = divmod(remainder, 60)
print '{:02}:{:02}:{:02}'.format(int(hours), int(minutes), int(seconds))
# result: 03:43:40
Posted by: Guest on June-10-2021
-1

format timedelta python

def strfdelta(tdelta, fmt):
    d = {"days": tdelta.days}
    d["hours"], rem = divmod(tdelta.seconds, 3600)
    d["minutes"], d["seconds"] = divmod(rem, 60)
    return fmt.format(**d)
Posted by: Guest on August-25-2020
11

python datetime string

import datetime

today = datetime.datetime.now()
date_time = today.strftime("%m/%d/%Y, %H:%M:%S")
print("date and time:",date_time)
Posted by: Guest on May-21-2020
0

phyton 2.7 convert timedelta to string

import datetime
start = datetime.datetime(2009,2,10,14,00)
end   = datetime.datetime(2009,2,10,16,00)
delta = end-start
print(str(delta))
# prints 2:00:00
Posted by: Guest on September-03-2020
0

datetime.timedelta format to string python

s = 13420
hours, remainder = divmod(s, 3600)
minutes, seconds = divmod(remainder, 60)
print '{:02}:{:02}:{:02}'.format(int(hours), int(minutes), int(seconds))
# result: 03:43:40
Posted by: Guest on June-10-2021
-1

format timedelta python

def strfdelta(tdelta, fmt):
    d = {"days": tdelta.days}
    d["hours"], rem = divmod(tdelta.seconds, 3600)
    d["minutes"], d["seconds"] = divmod(rem, 60)
    return fmt.format(**d)
Posted by: Guest on August-25-2020

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