Answers for "filter dictionary python"

Alphabet dictionary Python

alphabet = {
        'a' : '1', 
        'b' : '2', 
        'c' : '3', 
        'd' : '4', 
        'e' : '5', 
        'f' : '6', 
        'g' : '7', 
        'h' : '8', 
        'i' : '9', 
        'j' : '10', 
        'k' : '11', 
        'l' : '12', 
        'm' : '13', 
        'n' : '14', 
        'o' : '15', 
        'p' : '16', 
        'q' : '17', 
        'r' : '18', 
        's' : '19', 
        't' : '20', 
        'u' : '21', 
        'v' : '22', 
        'w' : '23', 
        'x' : '24', 
        'y' : '25', 
        'z' : '26'
    }

python filter a dictionary

d = dict(a=1, b=2, c=3, d=4, e=5)
print(d)
d1 = {x: d[x] for x in d.keys() if x not in ['a', 'b']}
print(d1)

filter list dict

fl = list(filter(lambda x: x['first'] == 'Christian', dictlist))

# you can't use `.property` because this is a dictionary, not a object
fl[0]['last']
# returns Doppler

filter dict

{k: v for k, v in points.items() if v[0] < 5 and v[1] < 5}

python filter dictionary

dict