Answers for "numpy np sign change in df pandas zero crossing"

numpy np sign change in df pandas zero crossing

> zero_crossings
array([ 3,  5,  9, 10, 11, 12, 15])

numpy np sign change in df pandas zero crossing

import numpy
a = [1, 2, 1, 1, -3, -4, 7, 8, 9, 10, -2, 1, -3, 5, 6, 7, -10]
zero_crossings = numpy.where(numpy.diff(numpy.sign(a)))[0]