python min in dictionary
a_dictionary = {"a": 1, "b": 2, "c": 3}
# get key with min value
min_key = min(a_dictionary, key=a_dictionary.get)
print(min_key)
# print output => "a"python min in dictionary
a_dictionary = {"a": 1, "b": 2, "c": 3}
# get key with min value
min_key = min(a_dictionary, key=a_dictionary.get)
print(min_key)
# print output => "a"python find smallest element in dictionary
d = {"A":3, "B":1, "C":100}
# find key with lowest value
best_key = min(d, key=d.get)
print(best_key)
# output: Bpython get the key with the max or min value in a dictionary
# Basic syntax:
key_with_max_value = max(dictionary, key=dictionary.get)
# Note, to get the max value itself, you can do either of the following:
max_value = dictionary[max(dictionary, key=dictionary.get)]
max_value = max(dictionary.values())
# Example usage:
dictionary = {"a": 1, "b": 2, "c": 3}
max(dictionary, key=dictionary.get)
--> 'c'python get min max value from a dictionary
d = {'A': 4,'B':10}
min_v = min(zip(d.values(), d.keys()))
# min_v is (4,'A')
max_v = max(zip(d.values(), d.keys()))
# max_v is (10,'B')Copyright © 2021 Codeinu
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