how to print error in try except python
try:
# some code
except Exception as e:
print("ERROR : "+str(e))how to print error in try except python
try:
# some code
except Exception as e:
print("ERROR : "+str(e))python except error as e
try:
#Do something
pass
except Exception as e:
#Do something
print(e)python try catch
try:
# Dangerous stuff
except ValueError:
# If you use try, at least 1 except block is mandatory!
# Handle it somehow / ignore
except (BadThingError, HorrbileThingError) as e:
# Hande it differently
except:
# This will catch every exception.
else:
# Else block is not mandatory.
# Dangerous stuff ended with no exception
finally:
# Finally block is not mandatory.
# This will ALWAYS happen after the above blocks.python except exception as e
try:
# Code to test / execute
print('Test')
except (SyntaxError, IndexError) as E: # specific exceptions
# Code in case of SyntaxError for example
print('Synthax or index error !')
except :
# Code for any other exception
print('Other error !')
else:
# Code if no exception caught
print('No error')
finally:
# Code executed after try block (success) or any exception (ie everytime)
print('Done')
# This code is out of try / catch bloc
print('Anything else')catch error data with except python
import sys
try:
S = 1/0 #Create Error
except: # catch *all* exceptions
e = sys.exc_info()
print(e) # (Exception Type, Exception Value, TraceBack)
############
# OR #
############
try:
S = 1/0
except ZeroDivisionError as e:
print(e) # ZeroDivisionError('division by zero')Copyright © 2021 Codeinu
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