python how to generate random number in a range
import random
# generates completely random number
x = random.random()
# generates a random int
x = random.randint()
# generates a random int in a range
x = random.randint(1, 100)
# NOTE: RANGE DOESN'T WORK FOR random.random()python random
# imports random
import random
# randint generates a random integar between the first parameter and the second
print(random.randint(1, 100))Generate random number from range python
import random
nbr = random.randint(1, 10)
print(nbr)
import numpy as np
uniform_nbrs = np.around(np.random.uniform(size=6), decimals=2)
print(uniform_nbrs)python random
# I know somebody else has made a similar thing from mine.
# Just letting you know that I didn't mean to copy his idea for this code.
# If you saw this, I recommend check the other answers out, too.
# Hope you guys understand...
from random import randint
# Prints a random number in between 1 and 1000
print(f"Here is a random number: {randint(1, 1000)}")random range python
from random import randrange
print(randrange(10))Copyright © 2021 Codeinu
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