Answers for "if main == name"

8

if __name__ == '__main__'

if __name__ == "__main__":
Posted by: Guest on June-16-2020
10

__name__== __main__ in python

# If the python interpreter is running that module (the source file)
# as the main program, it sets the special __name__ variable to have
# a value “__main__”. If this file is being imported from another 
# module, __name__ will be set to the module’s name.
if __name__=='__main__':
  # do something
Posted by: Guest on May-04-2020
2

if __name__ == '__main__': main()

print("before import")
def functionA():
    print("Function A")
def functionB():
    print(("Function B"))
print("before __name__")
if __name__ == '__main__':
    functionA()
    functionB()
print("after __name__")
#===Output===
#before import
#before __name__ guard
#Function A
#Function B
#after __name__ guard
Posted by: Guest on November-25-2020
1

What does if __name_=="_main__": do?

# Suppose this is foo.py.

print("before import")
import math

print("before functionA")
def functionA():
    print("Function A")

print("before functionB")
def functionB():
    print("Function B {}".format(math.sqrt(100)))

print("before __name__ guard")
if __name__ == '__main__':
    functionA()
    functionB()
print("after __name__ guard")
Posted by: Guest on February-02-2021
-1

explained if name main python

# Suppose this is foo.py.

print("before import")
import math

print("before functionA")
def functionA():
    print("Function A")

print("before functionB")
def functionB():
    print("Function B {}".format(math.sqrt(100)))

print("before __name__ guard")
if __name__ == '__main__':
    functionA()
    functionB()
print("after __name__ guard")
Posted by: Guest on March-08-2020
-1

__name__ == '__main__'

if __name__ == "__main__": main()
Posted by: Guest on May-03-2020

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