Answers for "datetime from string"

27

string to date python

import datetime

date_time_str = '2018-06-29 08:15:27.243860'
date_time_obj = datetime.datetime.strptime(date_time_str, '%Y-%m-%d %H:%M:%S.%f')

print('Date:', date_time_obj.date())
print('Time:', date_time_obj.time())
print('Date-time:', date_time_obj)
Posted by: Guest on June-01-2020
18

convert into date python

from datetime import datetime

datetime_str = '09/19/18 13:55:26'

datetime_object = datetime.strptime(datetime_str, '%m/%d/%y %H:%M:%S')

print(type(datetime_object))
print(datetime_object)  # printed in default format
Posted by: Guest on March-13-2020
17

convert into date python

date_str = '09-19-2018'

date_object = datetime.strptime(date_str, '%m-%d-%Y').date()
print(type(date_object))
print(date_object)  # printed in default formatting
Posted by: Guest on March-13-2020
8

python datetime from string

from datetime import datetime

datetime_object = datetime.strptime('Jun 1 2005  1:33PM', '%b %d %Y %I:%M%p')
Posted by: Guest on May-30-2020
3

python example strptime

from datetime import datetime

date_string = "21 June, 2018"

print("date_string =", date_string)
print("type of date_string =", type(date_string))

date_object = datetime.strptime(date_string, "%d %B, %Y")

print("date_object =", date_object)
print("type of date_object =", type(date_object))
Posted by: Guest on April-15-2020
2

convert str to datetime

import datetime

# str value "Apr 2, 2019" convert into any format. 
datetime.datetime.strptime('Apr 2, 2019', '%b %d, %Y').strftime('%a, %d %b %Y')
Posted by: Guest on May-13-2020

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