get self file name in python
import os
os.path.basename(__file__)
get name of a file in python
>>> f = open('/tmp/generic.png','r')
>>> f.name
'/tmp/generic.png'
>>> import os
>>> os.path.basename(f.name)
'generic.png'
python find file name
filesName = list(map(os.path.basename, glob.glob("..\yourPath\*txt")))
print(filesName)
get the name of a current script in python
Use __file__. If you want to omit the directory part (which might be present), you can use os.path.basename(__file__)
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