django group by
# If you mean to do aggregation you can use the aggregation features of the ORM:
from django.db.models import Count
Members.objects.values('designation').annotate(dcount=Count('designation'))
# This results in a query similar to:
SELECT designation, COUNT(designation) AS dcount
FROM members GROUP BY designation
#and the output would be of the form
[{'designation': 'Salesman', 'dcount': 2},
{'designation': 'Manager', 'dcount': 2}]objects.filter django
>>> Entry.objects.filter(blog_id=4)django queryset exists
if some_queryset.exists():
print("There is at least one object in some_queryset")django 3.0 queryset examples
>>> Entry.objects.filter(
... headline__startswith='What'
... ).exclude(
... pub_date__gte=datetime.date.today()
... ).filter(
... pub_date__gte=datetime.date(2005, 1, 30)
... )Copyright © 2021 Codeinu
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