get directory of file python
import os
dir_path = os.path.dirname(os.path.realpath(__file__))get directory of file python
import os
dir_path = os.path.dirname(os.path.realpath(__file__))get files in directory python
import os
files_and_directories = os.listdir("path/to/directory")list files in directory python
import os
print(os.listdir('/path/to/folder/to/list'))python get files in directory
from pathlib import Path
for txt_path in Path("/path/folder/directory").glob("*.txt"):
print(txt_path)python find file in directory
# option A (i think this is faster, not in micropython)
import os
if os.path.isfile("test.dat"):
print("yes") #file found
else:
print("no") #file not found
# also this is posible
# from os.path import isfile
# if isfile("test.dat"):
# option B (posible in micropython)
import os
if "test.dat" in os.listdir():
print("yes") # file found
else:
print("no") # file not found
# os.lisdir() return a array whit all the files found in the directorypython list directory files
Python By Charming Caribou on Mar 26 2020
import os
def get_filepaths(directory):
"""
This function will generate the file names in a directory
tree by walking the tree either top-down or bottom-up. For each
directory in the tree rooted at directory top (including top itself),
it yields a 3-tuple (dirpath, dirnames, filenames).
"""
file_paths = [] # List which will store all of the full filepaths.
# Walk the tree.
for root, directories, files in os.walk(directory):
for filename in files:
# Join the two strings in order to form the full filepath.
filepath = os.path.join(root, filename)
file_paths.append(filepath) # Add it to the list.
return file_paths # Self-explanatory.
# Run the above function and store its results in a variable.
full_file_paths = get_filepaths("/Users/johnny/Desktop/TEST")Copyright © 2021 Codeinu
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