Answers for "python open file in directory"

3

python open each file in directory

import os
for filename in os.listdir(os.getcwd()):
   with open(os.path.join(os.cwd(), filename), 'r') as f:
Posted by: Guest on July-03-2020
12

get files in directory python

import os
files_and_directories = os.listdir("path/to/directory")
Posted by: Guest on June-12-2020
0

python open file same folder

import os
with open(os.path.join(sys.path[0], "my_file.txt"), "r") as f:
    print(f.read())
Posted by: Guest on June-10-2020
1

python get files in directory

from pathlib import Path
for txt_path in Path("/path/folder/directory").glob("*.txt"):
  print(txt_path)
Posted by: Guest on November-30-2020
1

python find file in directory

# option A (i think this is faster, not in micropython)

import os

if os.path.isfile("test.dat"):
	print("yes") #file found
else:
	print("no") #file not found

# also this is posible
# from os.path import isfile
# if isfile("test.dat"):


# option B (posible in micropython)

import os

if "test.dat" in os.listdir():
	print("yes") # file found
else:
	print("no") # file not found

# os.lisdir() return a array whit all the files found in the directory
Posted by: Guest on March-29-2021
2

open file in python directory

path = 'C:\\Users\\Username\\Path\\To\\File'
file=open(path, "r")
Posted by: Guest on May-13-2020

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