python default dictonary
from collections import defaultdict
d_int = defaultdict(int)
d_list = defaultdict(list)
def foo():
return 'default value'
d_foo = defaultdict(foo)
>>> d_int
defaultdict(<type 'int'>, {})
>>> d_list
defaultdict(<type 'list'>, {})
>>> d_foo
defaultdict(<function foo at 0x7f34a0a69578>, {})python defaultdict to dict
>>> #You can simply call dict:
>>> a
defaultdict(<type 'list'>, {'1': ['b', 'a'], '3': ['b'], '2': ['a']})
>>> dict(a)
{'1': ['b', 'a'], '3': ['b'], '2': ['a']}
# but remember that a defaultdict is a dict
# (with some special behavior, check source):
>>> isinstance(a, dict)
Truefrom collections import defaultdict
>>> s = [('yellow', 1), ('blue', 2), ('yellow', 3), ('blue', 4), ('red', 1)]
>>> d = defaultdict(list)
>>> for k, v in s:
... d[k].append(v)
...
>>> d.items()
[('blue', [2, 4]), ('red', [1]), ('yellow', [1, 3])]Copyright © 2021 Codeinu
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