scrapy get current url
def parse(self, response):
current_url = response.request.urlscrapy get current url
def parse(self, response):
current_url = response.request.urlget href scrapy xpath
# with xpath
//div[@class='image']/a[1]/@href
# using css
Link = response.css('span.title a::attr(href)').getall()Copyright © 2021 Codeinu
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