how can I sort a dictionary in python according to its values?
s = {1: 1, 7: 2, 4: 2, 3: 1, 8: 1}
k = dict(sorted(s.items(),key=lambda x:x[0],reverse = True))
print(k)how can I sort a dictionary in python according to its values?
s = {1: 1, 7: 2, 4: 2, 3: 1, 8: 1}
k = dict(sorted(s.items(),key=lambda x:x[0],reverse = True))
print(k)python reverse dict key order
# Python3 using reversed() + items()
test_dict = {'Hello' : 4, 'to' : 2, 'you' : 5}
rev_dict = dict(reversed(list(test_dict.items()))) # Reversing the dictionary
print("The original dictionary : " + str(test_dict))
print("The reversed order dictionary : " + str(rev_dict))
# Output:
"The original dictionary : {'Hello': 4, 'to': 2, 'you': 5}"
"The reversed order dictionary : {'you': 5, 'to': 2, 'Hello': 4}"Copyright © 2021 Codeinu
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