how to sort a dictionary by value in python
import operator
x = {1: 2, 3: 4, 4: 3, 2: 1, 0: 0}
sorted_x = sorted(x.items(), key=operator.itemgetter(1))
# Sort by key
import operator
x = {1: 2, 3: 4, 4: 3, 2: 1, 0: 0}
sorted_x = sorted(x.items(), key=operator.itemgetter(0))how to sort dict by value
dict1 = {1: 1, 2: 9, 3: 4}
sorted_dict = {}
sorted_keys = sorted(dict1, key=dict1.get) # [1, 3, 2]
for w in sorted_keys:
sorted_dict[w] = dict1[w]
print(sorted_dict) # {1: 1, 3: 4, 2: 9}python sort array of dictionary by value
my_list = sorted(my_list, key=lambda k: k['name'])Copyright © 2021 Codeinu
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