how can I sort a dictionary in python according to its values?
s = {1: 1, 7: 2, 4: 2, 3: 1, 8: 1}
k = dict(sorted(s.items(),key=lambda x:x[0],reverse = True))
print(k)how can I sort a dictionary in python according to its values?
s = {1: 1, 7: 2, 4: 2, 3: 1, 8: 1}
k = dict(sorted(s.items(),key=lambda x:x[0],reverse = True))
print(k)sort list of dictionaries by key python
newlist = sorted(list_to_be_sorted, key=lambda k: k['name'])python sort dict by key
A={1:2, -1:4, 4:-20}
{k:A[k] for k in sorted(A)}
output:
{-1: 4, 1: 2, 4: -20}how to sort a dictionary
markdict = {"Tom":67, "Tina": 54, "Akbar": 87, "Kane": 43, "Divya":73}
marklist = sorted(markdict.items(), key=lambda x:x[1])
sortdict = dict(marklist)
print(sortdict)sort dictionary by key
dictionary_items = a_dictionary.items()
sorted_items = sorted(dictionary_items)Copyright © 2021 Codeinu
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