Answers for "sort dict by key python"

how can I sort a dictionary in python according to its values?

s = {1: 1, 7: 2, 4: 2, 3: 1, 8: 1}
k = dict(sorted(s.items(),key=lambda x:x[0],reverse = True))
print(k)

sort list of dictionaries by key python

newlist = sorted(list_to_be_sorted, key=lambda k: k['name'])

python sort dict by key

A={1:2, -1:4, 4:-20}
{k:A[k] for k in sorted(A)}

output:
{-1: 4, 1: 2, 4: -20}

sort the dictionary in python

d = {2: 3, 1: 89, 4: 5, 3: 0}
od = sorted(d.items())
print(od)

sort dictionary

#for dictionary d
sorted(d.items(), key=lambda x: x[1]) #for inceasing order
sorted(d.items(), key=lambda x: x[1], reverse=True) # for decreasing order
#it will return list of key value pair tuples

how to sort a dictionary py

orders = {
	'cappuccino': 54,
	'latte': 56,
	'espresso': 72,
	'americano': 48,
	'cortado': 41
}

sort_orders = sorted(orders.items(), key=lambda x: x[1], reverse=True)

for i in sort_orders:
	print(i[0], i[1])