Answers for "sorting dictionary in python2.7 by value"

how can I sort a dictionary in python according to its values?

s = {1: 1, 7: 2, 4: 2, 3: 1, 8: 1}
k = dict(sorted(s.items(),key=lambda x:x[0],reverse = True))
print(k)

Posted by: Guest on November-23-2020

sort dict by value

>>> x = {1: 2, 3: 4, 4: 3, 2: 1, 0: 0}
>>> {k: v for k, v in sorted(x.items(), key=lambda item: item[1])}
{0: 0, 2: 1, 1: 2, 4: 3, 3: 4}

Posted by: Guest on November-25-2020

sorting-a-dictionary-by-value-then-by-key

[(14,2), (12,2), (9,1)]  # output from print 
[(90,4), (99,3), (101,1), (100,1), (92,1)]

Posted by: Guest on March-09-2021

Code answers related to "sorting dictionary in python2.7 by value"