how can I sort a dictionary in python according to its values?
s = {1: 1, 7: 2, 4: 2, 3: 1, 8: 1}
k = dict(sorted(s.items(),key=lambda x:x[0],reverse = True))
print(k)how can I sort a dictionary in python according to its values?
s = {1: 1, 7: 2, 4: 2, 3: 1, 8: 1}
k = dict(sorted(s.items(),key=lambda x:x[0],reverse = True))
print(k)sort list of dictionaries by key python
newlist = sorted(list_to_be_sorted, key=lambda k: k['name'])python sort dict by key
A={1:2, -1:4, 4:-20}
{k:A[k] for k in sorted(A)}
output:
{-1: 4, 1: 2, 4: -20}python sort dictionary by key
In [1]: import collections
In [2]: d = {2:3, 1:89, 4:5, 3:0}
In [3]: od = collections.OrderedDict(sorted(d.items()))
In [4]: od
Out[4]: OrderedDict([(1, 89), (2, 3), (3, 0), (4, 5)])sort dict of dicts by key
channels = {
'24': {'type': 'plain', 'table_name': 'channel.items.AuctionChannel'},
'26': {'type': 'plain', 'table_name': 'channel.gm.DeleteAvatarChannel'},
'27': {'type': 'plain', 'table_name': 'channel.gm.AvatarMoneyChannel'},
'20': {'type': 'plain', 'table_name': 'channel.gm.AvatarMoneyAssertChannel'},
'21': {'type': 'plain', 'table_name': 'channel.gm.AvatarKillMobComplexChannel'},
'22': {'type': 'plain', 'table_name': 'channel.gm.DistributionMarkChannel'},
'23': {'type': 'plain', 'table_name': 'channel.gm.MailChannel'}
}
channels = collection.OrderedDict(sorted(channels.items(), key=lambda item: item[0]))
for key,value in channels.items():
print(key, ':', value)Copyright © 2021 Codeinu
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