how can I sort a dictionary in python according to its values?
s = {1: 1, 7: 2, 4: 2, 3: 1, 8: 1}
k = dict(sorted(s.items(),key=lambda x:x[0],reverse = True))
print(k)how can I sort a dictionary in python according to its values?
s = {1: 1, 7: 2, 4: 2, 3: 1, 8: 1}
k = dict(sorted(s.items(),key=lambda x:x[0],reverse = True))
print(k)python sort dictionary alphabetically by key
sortednames=sorted(dictUsers.keys(), key=lambda x:x.lower())python dictionary sort by value then alphabetically
sortedList = sorted(h, key=lambda k: (-k[1], k[0]))Copyright © 2021 Codeinu
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