Answers for "sort dictionary by value, print out key-value pairs that have same value"

12

how to sort a dictionary by value in python

import operator
x = {1: 2, 3: 4, 4: 3, 2: 1, 0: 0}
sorted_x = sorted(x.items(), key=operator.itemgetter(1))


# Sort by key
import operator
x = {1: 2, 3: 4, 4: 3, 2: 1, 0: 0}
sorted_x = sorted(x.items(), key=operator.itemgetter(0))
Posted by: Guest on November-27-2019
0

sort dict of dicts by key

channels = {
'24': {'type': 'plain', 'table_name': 'channel.items.AuctionChannel'}, 
'26': {'type': 'plain', 'table_name': 'channel.gm.DeleteAvatarChannel'}, 
'27': {'type': 'plain', 'table_name': 'channel.gm.AvatarMoneyChannel'}, 
'20': {'type': 'plain', 'table_name': 'channel.gm.AvatarMoneyAssertChannel'}, 
'21': {'type': 'plain', 'table_name': 'channel.gm.AvatarKillMobComplexChannel'}, 
'22': {'type': 'plain', 'table_name': 'channel.gm.DistributionMarkChannel'}, 
'23': {'type': 'plain', 'table_name': 'channel.gm.MailChannel'}
}

channels = collection.OrderedDict(sorted(channels.items(), key=lambda item: item[0]))
for key,value in channels.items():
    print(key, ':', value)
Posted by: Guest on September-05-2020

Code answers related to "sort dictionary by value, print out key-value pairs that have same value"

Python Answers by Framework

Browse Popular Code Answers by Language