Answers for "zip file python"

5

how to unzip files using zipfile module python

import zipfile
with zipfile.ZipFile("file.zip","r") as zip_ref:
    zip_ref.extractall("targetdir")
Posted by: Guest on May-07-2020
0

python zip files

import shutil
shutil.make_archive(output_filename, 'zip', dir_name)
Posted by: Guest on July-07-2021
0

extracting zip files python

import os
import optparse
import zipfile

def get_arguments():
    parser = optparse.OptionParser()
    parser.add_option("--src","--source",dest="paths", help="Removing file with extension .SRT and .VTT")
    (options,arguments)=parser.parse_args()
    if not options.paths:
        parser.error("[-] Please specify source, use --help for more info.")
    return options


def Source_folder(folder_path):
    print('[+] Extracting zip file')
    for path, dir_list, file_list in os.walk(folder_path):
        try:
            for file_name in file_list:
                if file_name.endswith(".zip"):
                    abs_file_path = os.path.join(path, file_name)
                    parent_path = os.path.split(abs_file_path)[0]
                    output_folder_name = os.path.splitext(abs_file_path)[0]
                    output_path = os.path.join(parent_path, output_folder_name)

                    zip_obj = zipfile.ZipFile(abs_file_path, 'r')
                    zip_obj.extractall(output_path)
                    zip_obj.close()

        except FileNotFoundError:
            print('Error', file_name)


options = get_arguments()
Source_folder(options.paths)
Posted by: Guest on October-05-2020
1

zip python

>>> x = [1, 2, 3]
>>> y = [4, 5, 6]
>>> zipped = zip(x, y)
>>> list(zipped)
[(1, 4), (2, 5), (3, 6)]
>>> x2, y2 = zip(*zip(x, y))
>>> x == list(x2) and y == list(y2)
True
Posted by: Guest on April-30-2020

Python Answers by Framework

Browse Popular Code Answers by Language