Answers for "root.filename = filedialog.askopenfilename"

4

askopenfilename

filename2 =  filedialog.askopenfilename(title = "Select file",filetypes = (("Excel files", ".xlsx .xls"),))
Posted by: Guest on September-13-2020
1

tkfiledialog python 3 example

from  tkinter import *
root = Tk()
root.filename =  filedialog.askopenfilename(initialdir = "E:/Images",title = "choose your file",filetypes = (("jpeg files","*.jpg"),("all files","*.*")))
print (root.filename)
root.withdraw()
Posted by: Guest on December-10-2020

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