how to print error in try except python
try:
# some code
except Exception as e:
print("ERROR : "+str(e))how to print error in try except python
try:
# some code
except Exception as e:
print("ERROR : "+str(e))catch error python
import traceback
dict = {'a':3,'b':5,'c':8}
try:
print(dict[q])
except:
traceback.print_exc()
# This will trace you back to the line where everything went wrong.
# So in this case you will get back line 5python catch exception
try:
# Code to test / execute
print('Test')
except (SyntaxError, IndexError) as E: # specific exceptions
# Code in case of SyntaxError for example
print('Synthax or index error !')
except :
# Code for any other exception
print('Other error !')
else:
# Code if no exception caught
print('No error')
finally:
# Code executed after try block (success) or any exception (ie everytime)
print('Done')
# This code is out of try / catch bloc
print('Anything else')python check for exception
try: # put here the code that you expect to error
# code
except ValueError: # if you want to catch a ValueError
# NOTE: you CANNOT catch a syntax error
# (UNLESS you are trying to execute code from a string with eval())
# code if python caught the exception
except NameError: # you can catch multiple types of errors!
# TIP: you can leave the error type blank to make python catch all types of errors!
# code if another exception is caught (this is pretty much a modified if statement)
else: # if no error has been caught do the following:
# code if no exception has been caughtCopyright © 2021 Codeinu
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