how to print error in try except python
try:
# some code
except Exception as e:
print("ERROR : "+str(e))how to print error in try except python
try:
# some code
except Exception as e:
print("ERROR : "+str(e))python try except
import sys
try:
f = open('myfile.txt')
s = f.readline()
i = int(s.strip())
except OSError as err:
print("OS error: {0}".format(err))
except ValueError:
print("Could not convert data to an integer.")
except:
print("Unexpected error:", sys.exc_info()[0])
raisetry except python
try:
Age = int(input("Your Age:- "))
except ValueError:
print("Age not in Intger form")try except python
# Python try: except:
try:
print(a + b) # Program will try the add b to a
except:
print("There was an error") # If the program will have an error in the try block
# The except block will run
# except block will run and then the program will continue to run
# Examples:
a = 1
b = 1 # <===== no error, except block skipped
a = 1
b = 'one' # <===== error, except block runtry except python
try: #try to do the following
print("Hi there")
except: #If what is meant to happen in (try) fails, do this.
print("A error happened with the code above")Copyright © 2021 Codeinu
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