how to print error in try except python
try:
# some code
except Exception as e:
print("ERROR : "+str(e))how to print error in try except python
try:
# some code
except Exception as e:
print("ERROR : "+str(e))python try catch
try:
# Dangerous stuff
except ValueError:
# If you use try, at least 1 except block is mandatory!
# Handle it somehow / ignore
except (BadThingError, HorrbileThingError) as e:
# Hande it differently
except:
# This will catch every exception.
else:
# Else block is not mandatory.
# Dangerous stuff ended with no exception
finally:
# Finally block is not mandatory.
# This will ALWAYS happen after the above blocks.except as Exception:
>>> def catch():
... try:
... asd()
... except Exception as e:
... print e.message, e.args
...
>>> catch()
global name 'asd' is not defined ("global name 'asd' is not defined",)error handling Pyhtin
# taking input from the user
try:
age = int(input("Please enter your age: "))
print(age)
except:
print("please enter a number instead! ")
print('bye')
# if you wanna ask their age until they enter the correct number use While Loop
while True:
try:
age = int(input("Please enter your age: "))
print(age)
except:
print("please enter a number instead! ")
else:
breakpython error handling
try:
#insert code here
except:
#insert code that will run if the above code runs into an error.
except ValueError:
#insert code that will run if the above code runs into a specific error.
#(For example, a ValueError)Copyright © 2021 Codeinu
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