how to print error in try except python
try:
# some code
except Exception as e:
print("ERROR : "+str(e))how to print error in try except python
try:
# some code
except Exception as e:
print("ERROR : "+str(e))python except print error type
>>> try:
... raise Exception('spam', 'eggs')
... except Exception as inst:
... print(type(inst)) # the exception instance
... print(inst.args) # arguments stored in .args
... print(inst) # __str__ allows args to be printed directly,
... # but may be overridden in exception subclasses
... x, y = inst.args # unpack args
... print('x =', x)
... print('y =', y)
...
<class 'Exception'>
('spam', 'eggs')
('spam', 'eggs')
x = spam
y = eggstry except python
# Python try: except:
try:
print(a + b) # Program will try the add b to a
except:
print("There was an error") # If the program will have an error in the try block
# The except block will run
# except block will run and then the program will continue to run
# Examples:
a = 1
b = 1 # <===== no error, except block skipped
a = 1
b = 'one' # <===== error, except block runCopyright © 2021 Codeinu
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