how to print error in try except python
try:
# some code
except Exception as e:
print("ERROR : "+str(e))how to print error in try except python
try:
# some code
except Exception as e:
print("ERROR : "+str(e))except as Exception:
>>> def catch():
... try:
... asd()
... except Exception as e:
... print e.message, e.args
...
>>> catch()
global name 'asd' is not defined ("global name 'asd' is not defined",)python raise error exit
# There are 3 approaches, the first as lvc mentioned is using sys.exit
sys.exit('My error message')
# The second way is using print, print can write almost anything including an error message
print >>sys.stderr, "fatal error" # Python 2.x
print("fatal error", file=sys.stderr) # Python 3.x
# The third way is to rise an exception which I don't like because it can be try-catch
raise SystemExit('error in code want to exit')
# it can be ignored like this
try:
raise SystemExit('error in code want to exit')
except:
print("program is still open")error handling in python
try:
print(x)
except SyntaxError:
print("There is a SyntaxError in your code")
except NameError:
print("There is a NameError in your code")
except TypeError:
print("There is a TypeError in your code")Copyright © 2021 Codeinu
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