how to print error in try except python
try:
# some code
except Exception as e:
print("ERROR : "+str(e))how to print error in try except python
try:
# some code
except Exception as e:
print("ERROR : "+str(e))python try catch
try:
# Dangerous stuff
except ValueError:
# If you use try, at least 1 except block is mandatory!
# Handle it somehow / ignore
except (BadThingError, HorrbileThingError) as e:
# Hande it differently
except:
# This will catch every exception.
else:
# Else block is not mandatory.
# Dangerous stuff ended with no exception
finally:
# Finally block is not mandatory.
# This will ALWAYS happen after the above blocks.try except
try:
print("I will try to print this line of code")
except:
print("I will print this line of code if an error is encountered")
else:
print("I will print this line of code if there's no error encountered")
finally:
print("I will print this line of code even if there's an error or no error encountered")try except python
try: #try to do the following
print("Hi there")
except: #If what is meant to happen in (try) fails, do this.
print("A error happened with the code above")try catch block
const input = require('readline-sync');
let animals = [{name: 'cat'}, {name: 'dog'}];
let index = Number(input.question("Enter index of animal:"));
try {
console.log('animal at index:', animals[index].name);
} catch(err) {
console.log("We caught a TypeError, but our program continues to run!");
console.log("You tried to access an animal at index:", index);
}
console.log("the code goes on...");Copyright © 2021 Codeinu
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