throwing an exception python
raise Exception("message")
raise exception in python
raise Exception('I know Python!') # Don't! If you catch, likely to hide bugs.
raise exception in python
#raise exception
raise ValueError('A very specific bad thing happened.')
how to use except statement in python
>>> def divide(x, y):
... try:
... result = x / y
... except ZeroDivisionError:
... print("division by zero!")
... else:
... print("result is", result)
... finally:
... print("executing finally clause")
...
>>> divide(2, 1)
result is 2.0
executing finally clause
>>> divide(2, 0)
division by zero!
executing finally clause
>>> divide("2", "1")
executing finally clause
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
File "<stdin>", line 3, in divide
TypeError: unsupported operand type(s) for /: 'str' and 'str'
python raise exception
# this raises a "NameError"
>>> raise NameError('HiThere')
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
NameError: HiThere
python raise error exit
# There are 3 approaches, the first as lvc mentioned is using sys.exit
sys.exit('My error message')
# The second way is using print, print can write almost anything including an error message
print >>sys.stderr, "fatal error" # Python 2.x
print("fatal error", file=sys.stderr) # Python 3.x
# The third way is to rise an exception which I don't like because it can be try-catch
raise SystemExit('error in code want to exit')
# it can be ignored like this
try:
raise SystemExit('error in code want to exit')
except:
print("program is still open")
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