Answers for "python3 print exception"

1

catch error data with except python

import sys
try:
	S = 1/0 #Create Error
except: # catch *all* exceptions
    e = sys.exc_info()
    print(e) # (Exception Type, Exception Value, TraceBack)

############
#    OR    #
############
try:
	S = 1/0
except ZeroDivisionError as e:
    print(e) # ZeroDivisionError('division by zero')
Posted by: Guest on June-11-2020
-1

python try except print error

1 (x,y) = (5,0)
   2 try:
   3   z = x/y
   4 except ZeroDivisionError as e:
   5   z = e # representation: "<exceptions.ZeroDivisionError instance at 0x817426c>"
   6 print z # output: "integer division or modulo by zero"
Posted by: Guest on January-15-2021

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