how to print error in try except python
try:
# some code
except Exception as e:
print("ERROR : "+str(e))
how to print error in try except python
try:
# some code
except Exception as e:
print("ERROR : "+str(e))
python get exception message
try:
with open(filepath,'rb') as f:
con.storbinary('STOR '+ filepath, f)
logger.info('File successfully uploaded to '+ FTPADDR)
except Exception as e: # work on python 3.x
logger.error('Failed to upload to ftp: '+ str(e))
except as Exception:
>>> def catch():
... try:
... asd()
... except Exception as e:
... print e.message, e.args
...
>>> catch()
global name 'asd' is not defined ("global name 'asd' is not defined",)
python catch exception message
try:
# Code to test / execute
print('Test')
except (SyntaxError, IndexError) as E: # specific exceptions
# Code in case of SyntaxError for example
print('Synthax or index error !')
except :
# Code for any other exception
print('Other error !')
else:
# Code if no exception caught
print('No error')
finally:
# Code executed after try block (success) or any exception (ie everytime)
print('Done')
# This code is out of try / catch bloc
print('Anything else')
catch error data with except python
import sys
try:
S = 1/0 #Create Error
except: # catch *all* exceptions
e = sys.exc_info()
print(e) # (Exception Type, Exception Value, TraceBack)
############
# OR #
############
try:
S = 1/0
except ZeroDivisionError as e:
print(e) # ZeroDivisionError('division by zero')
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