python find the key with max value
a_dictionary = {"a": 1, "b": 2, "c": 3}
# get key with max value
max_key = max(a_dictionary, key=a_dictionary.get)
print(max_key)python find the key with max value
a_dictionary = {"a": 1, "b": 2, "c": 3}
# get key with max value
max_key = max(a_dictionary, key=a_dictionary.get)
print(max_key)python get the key with the max or min value in a dictionary
# Basic syntax:
key_with_max_value = max(dictionary, key=dictionary.get)
# Note, to get the max value itself, you can do either of the following:
max_value = dictionary[max(dictionary, key=dictionary.get)]
max_value = max(dictionary.values())
# Example usage:
dictionary = {"a": 1, "b": 2, "c": 3}
max(dictionary, key=dictionary.get)
--> 'c'find the max value in dictionary python
my_dict = {'a': 5, 'b': 10, 'c': 6, 'd': 12, 'e': 7}
max(my_dict, key=my_dict.get) # returns 'd'python max key dictionary key getter
from operator import itemgetter
items = [
{'a': 1, 'b': 99},
{'a': 2, 'b': 88},
{'a': 3, 'b': 77},
]
print(max(items, key=itemgetter('a')))
print(max(items, key=itemgetter('b')))Python find max in list of dict by value
lst = [{'price': 99, 'barcode': '2342355'}, {'price': 88, 'barcode': '2345566'}]
maxPricedItem = max(lst, key=lambda x:x['price'])
minPricedItem = min(lst, key=lambda x:x['price'])Copyright © 2021 Codeinu
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