python find the key with max value
a_dictionary = {"a": 1, "b": 2, "c": 3}
# get key with max value
max_key = max(a_dictionary, key=a_dictionary.get)
print(max_key)python find the key with max value
a_dictionary = {"a": 1, "b": 2, "c": 3}
# get key with max value
max_key = max(a_dictionary, key=a_dictionary.get)
print(max_key)python get the key with the max or min value in a dictionary
# Basic syntax:
key_with_max_value = max(dictionary, key=dictionary.get)
# Note, to get the max value itself, you can do either of the following:
max_value = dictionary[max(dictionary, key=dictionary.get)]
max_value = max(dictionary.values())
# Example usage:
dictionary = {"a": 1, "b": 2, "c": 3}
max(dictionary, key=dictionary.get)
--> 'c'max of a dict
dic={0: 1.4984074067880424, 1: 1.0984074067880423, 2: 1.8984074067880425, 3: 2.2984074067880425, 4: 2.2984074067880425}
max_value = max(dic.values()) # maximum value
max_keys = [k for k, v in dic.items() if v == max_value] # getting all keys containing the `maximum`
print(max_value, max_keys)find the max value in dictionary python
my_dict = {'a': 5, 'b': 10, 'c': 6, 'd': 12, 'e': 7}
max(my_dict, key=my_dict.get) # returns 'd'python max key dictionary key getter
from operator import itemgetter
items = [
{'a': 1, 'b': 99},
{'a': 2, 'b': 88},
{'a': 3, 'b': 77},
]
print(max(items, key=itemgetter('a')))
print(max(items, key=itemgetter('b')))max element in dictionary python
import operator
stats = {'a':1000, 'b':3000, 'c': 100}
max(stats.iteritems(), key=operator.itemgetter(1))[0]Copyright © 2021 Codeinu
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