python find the key with max value
a_dictionary = {"a": 1, "b": 2, "c": 3} # get key with max value max_key = max(a_dictionary, key=a_dictionary.get) print(max_key)
python find the key with max value
a_dictionary = {"a": 1, "b": 2, "c": 3} # get key with max value max_key = max(a_dictionary, key=a_dictionary.get) print(max_key)
python how to find the highest number in a dictionary
a_dictionary = {"a": 1, "b": 2, "c": 3} max_key = max(a_dictionary, key=a_dictionary.get) get key with max value print(max_key)
max of a dict
dic={0: 1.4984074067880424, 1: 1.0984074067880423, 2: 1.8984074067880425, 3: 2.2984074067880425, 4: 2.2984074067880425} max_value = max(dic.values()) # maximum value max_keys = [k for k, v in dic.items() if v == max_value] # getting all keys containing the `maximum` print(max_value, max_keys)
python max key dictionary key getter
from operator import itemgetter items = [ {'a': 1, 'b': 99}, {'a': 2, 'b': 88}, {'a': 3, 'b': 77}, ] print(max(items, key=itemgetter('a'))) print(max(items, key=itemgetter('b')))
find the highest 3 values in a dictionary.
from collections import Counter # Initial Dictionary my_dict = {'t': 3, 'u': 4, 't': 6, 'o': 5, 'r': 21} k = Counter(my_dict) # Finding 3 highest values high = k.most_common(3) print("Dictionary with 3 highest values:") print("Keys: Values") for i in high: print(i[0]," :",i[1]," ")
max element in dictionary python
import operator stats = {'a':1000, 'b':3000, 'c': 100} max(stats.iteritems(), key=operator.itemgetter(1))[0]
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