sort list of dictionaries python by value
newlist = sorted(list_to_be_sorted, key=lambda k: k['name'])
sort list of dictionaries python by value
newlist = sorted(list_to_be_sorted, key=lambda k: k['name'])
how to sort dictionary in python by value
# your dictionary
a = {'a':4, 'c':5, 'b':3, 'd':0}
# sort x by keys
a_keys = dict(sorted(a.items(),key=lambda x:x[0],reverse = False)) # ascending order
# output: {'a': 4, 'b': 3, 'c': 5, 'd': 0}
# # sort x by values
a_values = dict(sorted(a.items(),key=lambda x:x[1],reverse = False)) # ascending order
# output: {'d': 0, 'b': 3, 'a': 4, 'c': 5}
how to sort dict by value
dict1 = {1: 1, 2: 9, 3: 4}
sorted_dict = {}
sorted_keys = sorted(dict1, key=dict1.get) # [1, 3, 2]
for w in sorted_keys:
sorted_dict[w] = dict1[w]
print(sorted_dict) # {1: 1, 3: 4, 2: 9}
sort dict by value
x = {1: 2, 3: 4, 4: 3, 2: 1, 0: 0}
{k: v for k, v in sorted(x.items(), key=lambda item: item[1])}
{0: 0, 2: 1, 1: 2, 4: 3, 3: 4}
Copyright © 2021 Codeinu
Forgot your account's password or having trouble logging into your Account? Don't worry, we'll help you to get back your account. Enter your email address and we'll send you a recovery link to reset your password. If you are experiencing problems resetting your password contact us