python index of max value in list
# any list
a = [1, 7, 3, 12, 5]
# index of minimum element
# if more than 1 minimum,
# first index is returned
min_index = a.index(min(a))
# index of maximum element
max_index = a.index(max(a))
python index of max value in list
# any list
a = [1, 7, 3, 12, 5]
# index of minimum element
# if more than 1 minimum,
# first index is returned
min_index = a.index(min(a))
# index of maximum element
max_index = a.index(max(a))
python how to return max num index
import numpy as np
x=[1,2,3,4,5]
max_index=np.argmax(x)
# return the index of the maximun element
# max_index has the value 4
get index of highest value in array python
result = numpy.where(arr == numpy.amax(arr))
python index max list
number_list = [1, 2, 3]
max_value = max(number_list)
# Return the max value of the list
max_index = number_list.index(max_value)
# Find the index of the max value
print(max_index)
# get the largest number in a list and print its indexes
numbers = 1,3,11,42,12,4001
highestnumber = -999
for i in numbers:
if i > highestnumber:
highestnumber = i
print(numbers.index(highestnumber))
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