sort tuple by first element python
a = [(5,8), (3,4), (9,7)] #sort by first element in tuple result = sorted(a, key=lambda tup: tup[0]) #OR to do inplace sort: a.sorted(key = lambda tup: tup[0]) # output [(3, 4), (5, 8), (9, 7)]
sort tuple by first element python
a = [(5,8), (3,4), (9,7)] #sort by first element in tuple result = sorted(a, key=lambda tup: tup[0]) #OR to do inplace sort: a.sorted(key = lambda tup: tup[0]) # output [(3, 4), (5, 8), (9, 7)]
how to sort a list by the second element in tuple python
# lists_of_tuples = [('item', 'price'), ('item', 'price'), ('item', 'price')] def sort_prices(list_of_tuples): #sort the list b*y the price of each tuple list_of_tuples.sort(key=lambda x: x[1], reverse=True) #earse the "reverse" part to sort in small to big. return list_of_tuples, print(list_of_tuples)
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