sort tuple by first element python
a = [(5,8), (3,4), (9,7)]
#sort by first element in tuple
result = sorted(a, key=lambda tup: tup[0])
#OR to do inplace sort:
a.sorted(key = lambda tup: tup[0])
# output
[(3, 4), (5, 8), (9, 7)]sort tuple by first element python
a = [(5,8), (3,4), (9,7)]
#sort by first element in tuple
result = sorted(a, key=lambda tup: tup[0])
#OR to do inplace sort:
a.sorted(key = lambda tup: tup[0])
# output
[(3, 4), (5, 8), (9, 7)]how to sort a list by the second element in tuple python
# lists_of_tuples = [('item', 'price'), ('item', 'price'), ('item', 'price')]
def sort_prices(list_of_tuples): #sort the list b*y the price of each tuple
list_of_tuples.sort(key=lambda x: x[1], reverse=True) #earse the "reverse" part to sort in small to big.
return list_of_tuples, print(list_of_tuples)pyhon sort a list of tuples
sorted([('abc', 121),('abc', 231),('abc', 148), ('abc',221)], key=lambda x: x[1])pyhon sort a list of tuples
# Python program to sort a list of tuples by the second Item
# Function to sort the list of tuples by its second item
def Sort_Tuple(tup):
# Getting length of list of tuples
lst = len(tup)
for i in range(0, lst):
for j in range(0, lst-i-1):
if (tup[j][1] > tup[j + 1][1]):
temp = tup[j]
tup[j]= tup[j + 1]
tup[j + 1]= temp
return tuphow to sort tuples in python
# If you have a tuple, first convert it to a list:
a = (3,1,2)
a = list(a)
# And now you can just use the inbuilt function ( .sort() ):
a.sort()
print(a)
>>> [1,2,3]
# ^ by using .sort() you are modifying the original list / tuple, however
# if you want to make a sorted copy of the list / tuple, then you use this:
a = [3, 6, 8, 2, 78, 1, 23, 45, 9]
print(sorted(a))
>>> [1, 2, 3, 6, 8, 9, 23, 45, 78]
# This also works with the alphabet or a combination between letters and
# numbers.Copyright © 2021 Codeinu
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