how to sort a list by the second element in tuple python
# lists_of_tuples = [('item', 'price'), ('item', 'price'), ('item', 'price')]
def sort_prices(list_of_tuples): #sort the list b*y the price of each tuple
list_of_tuples.sort(key=lambda x: x[1], reverse=True) #earse the "reverse" part to sort in small to big.
return list_of_tuples, print(list_of_tuples)count number of times an element is occuring in an array in javascript
Array.prototype.frequencies = function() {
var l = this.length, result = {all:[]};
while (l--){
result[this[l]] = result[this[l]] ? ++result[this[l]] : 1;
}
// all pairs (label, frequencies) to an array of arrays(2)
for (var l in result){
if (result.hasOwnProperty(l) && l !== 'all'){
result.all.push([ l,result[l] ]);
}
}
return result;
};
var freqs = [5, 5, 5, 2, 2, 2, 2, 2, 9, 4].frequencies();
alert(freqs[2]); //=> 5
// or
var freqs = '1,1,2,one,one,2,2,22,three,four,five,three,three,five'
.split(',')
.frequencies();
alert(freqs.three); //=> 3Return the number of elements in this RDD.
sc.parallelize([2, 3, 4]).count()
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