Answers for "sort dictionary by value python descending by key"

python sort dictionary by value descending

Python Code:
import operator
d = {1: 2, 3: 4, 4: 3, 2: 1, 0: 0}
print('Original dictionary : ',d)
sorted_d = dict(sorted(d.items(), key=operator.itemgetter(1)))
print('Dictionary in ascending order by value : ',sorted_d)
sorted_d = dict(sorted(d.items(), key=operator.itemgetter(1),reverse=True))
print('Dictionary in descending order by value : ',sorted_d)

Sample Output:
Original dictionary :  {1: 2, 3: 4, 4: 3, 2: 1, 0: 0}
Dictionary in ascending order by value :  {0: 0, 2: 1, 1: 2, 4: 3, 3: 4}
Dictionary in descending order by value :  {3: 4, 4: 3, 1: 2, 2: 1, 0: 0}

order dictionary by value python

x = {1: 2, 3: 4, 4: 3, 2: 1, 0: 0}
sorted_dict = {k: v for k, v in sorted(x.items(), key=lambda item: item[1])}
print(sorted_dict)
#{0: 0, 2: 1, 1: 2, 4: 3, 3: 4}